# Gravity dominated film-condensation in a porous medium

(Difference between revisions)
 Revision as of 17:58, 31 May 2010 (view source)← Older edit Revision as of 14:21, 2 June 2010 (view source)Newer edit → Line 12: Line 12: 5. The saturation temperature, Tsat, is constant. 5. The saturation temperature, Tsat, is constant. - [[Image:Chapter7 (31).gif|400 px|alt= Gravity dominated film-condensation on an inclined wall in a porous medium. | Figure 8.30 Gravity dominated film-condensation on an inclined wall in a porous medium.  ]] + [[Image:Chapter7 (18).jpg|400 px|alt= Gravity dominated film-condensation on an inclined wall in a porous medium. | Figure 8.30 Gravity dominated film-condensation on an inclined wall in a porous medium.  ]] Under these assumptions, the continuity, momentum, and energy equations for the liquid layer are Under these assumptions, the continuity, momentum, and energy equations for the liquid layer are

## Revision as of 14:21, 2 June 2010

When condensation is dominated by gravity, the effect of surface tension is negligible, and consequently, no two-phase region exists. Condensation along an inclined wall in a porous medium (See Fig. 8.30) will be discussed in this subsection. A porous medium saturated with dry vapor at its saturation temperature, Tsat, is bounded by an inclined impermeable wall with a temperature Tw (Tw < Tsat). Since the wall temperature is below saturation temperature, film condensation occurs on the inclined wall and the condensate flows downward due to gravity. It is assumed that the condensation is gravity-dominated and, therefore, that the liquid and vapor are separated by a sharp interface, not a two-phase region. In addition, the following assumptions are made by Cheng (1981) in order to obtain an analytical solution:

1. The condensate film is very thin compared to the length of the inclined wall ( ${{\delta }_{\ell }}\ll L$) so that boundary layer assumption is valid.

2. The properties for the porous medium, liquid, and vapor are independent from temperature.

3. The inclination angle, φ, is small enough for the gravity component in the normal direction of the surface to be negligible.

4. Darcy’s law is valid for both liquid and vapor phases.

5. The saturation temperature, Tsat, is constant.

Under these assumptions, the continuity, momentum, and energy equations for the liquid layer are $\frac{\partial {{u}_{\ell }}}{\partial x}+\frac{\partial {{v}_{\ell }}}{\partial y}=0$ (8.355) ${{u}_{\ell }}=\frac{K}{{{\mu }_{\ell }}}({{\rho }_{\ell }}-{{\rho }_{v}})g\cos \phi$ (8.356) ${{u}_{\ell }}\frac{\partial {{T}_{\ell }}}{\partial x}+{{v}_{\ell }}\frac{\partial {{T}_{\ell }}}{\partial y}={{\alpha }_{\ell }}\frac{{{\partial }^{2}}{{T}_{\ell }}}{\partial {{y}^{2}}}$ (8.357)

The boundary conditions at the wall are ${{v}_{\ell }}=0\begin{matrix} , & y=0 \\ \end{matrix}$ (8.358) ${{T}_{\ell }}={{T}_{w}}\begin{matrix} , & y=0 \\ \end{matrix}$ (8.359)

At the interface, the boundary conditions are ${{T}_{\ell }}={{T}_{sat}}\begin{matrix} , & y={{\delta }_{\ell }} \\ \end{matrix}$ (8.360) $\dot{{m}''}={{\rho }_{\ell }}\left( {{u}_{\ell }}\frac{d{{\delta }_{\ell }}}{dx}-{{v}_{\ell }} \right)\begin{matrix} , & y={{\delta }_{\ell }} \\ \end{matrix}$ (8.361) $\dot{{m}''}{{h}_{\ell v}}=-{{k}_{m\ell }}\frac{\partial T}{\partial y}\begin{matrix} , & y={{\delta }_{\ell }} \\ \end{matrix}$ (8.362)

where $\dot{{m}''}$ is mass flux of condensate across the interface, and ${{k}_{m\ell }}$ is thermal conductivity of the porous medium saturated with liquid. Combining of eqs. (8.361) and (8.362) yields ${{\rho }_{\ell }}{{h}_{\ell v}}\left( {{u}_{\ell }}\frac{d{{\delta }_{\ell }}}{dx}-{{v}_{\ell }} \right)=-{{k}_{m\ell }}\frac{\partial T}{\partial y}\begin{matrix} , & y={{\delta }_{\ell }} \\ \end{matrix}$ (8.363)

Introducing stream function ${{u}_{\ell }}=\frac{\partial \psi }{\partial y}\begin{matrix} , & {{v}_{\ell }}=-\frac{\partial \psi }{\partial x} \\ \end{matrix}$ (8.364)

and the following similarity variables: $\eta =\sqrt{R{{a}_{\ell x}}}\frac{y}{x}$ (8.365) $f(\eta )=\frac{\psi }{{{\alpha }_{\ell }}\sqrt{R{{a}_{\ell x}}}}$ (8.366) $\theta (\eta )=\frac{{{T}_{\ell }}-{{T}_{sat}}}{{{T}_{w}}-{{T}_{sat}}}$ (8.367)

where $R{{a}_{\ell x}}=\frac{({{\rho }_{\ell }}-{{\rho }_{v}})g\cos \phi Kx}{{{\mu }_{\ell }}{{\alpha }_{\ell }}}$ (8.368)

the governing equations and the corresponding boundary conditions become

f' = 1 (8.369)
2θ'' + fθ' = 0 (8.370)
f(0) = 0 (8.371)
θ(0) = 1 (8.372)
θ(ηδ) = 0 (8.373) $\text{J}{{\text{a}}_{\ell }}{\theta }'({{\eta }_{\delta }})=-\frac{1}{2}f({{\eta }_{\delta }})$ (8.374)

where ${{\eta }_{\delta }}=\sqrt{R{{a}_{\ell x}}}\frac{{{\delta }_{\ell }}}{x}$ (8.375)

is the dimensionless liquid film thickness and $\text{J}{{\text{a}}_{\ell }}=\frac{{{c}_{p\ell }}({{T}_{sat}}-{{T}_{w}})}{{{h}_{\ell v}}}$ (8.376)

is Jakob number that measures the degree of subcooling at the wall.

Integrating eq. (8.369) and considering eq. (8.371), one obtains

f = η (8.377)

which can be substituted into eqs. (8.370) and (8.374) to get

2θ'' + ηθ' = 0 (8.378) $\text{J}{{\text{a}}_{\ell }}{\theta }'({{\eta }_{\delta }})=-\frac{1}{2}{{\eta }_{\delta }}$ (8.379)

The solution of eq. (8.378) with eqs. (8.372) and (8.373) as boundary conditions is $\theta (\eta )=1-\frac{\text{erf}(\eta /2)}{\text{erf(}{{\eta }_{\delta }}/2)}$ (8.380)

where the dimensionless film thickness can be obtained by substituting eq. (8.380) into eq. (8.379): $\text{J}{{\text{a}}_{\ell }}=\sqrt{\frac{\pi {{\eta }_{\delta }}}{2}}\exp \left( \frac{\eta _{\delta }^{2}}{4} \right)\text{erf}\left( \frac{{{\eta }_{\delta }}}{2} \right)$ (8.381)

The heat flux at the wall is ${{{q}''}_{w}}=-{{k}_{m\ell }}{{\left( \frac{\partial {{T}_{\ell }}}{\partial y} \right)}_{y=0}}=\frac{{{k}_{m\ell }}({{T}_{sat}}-{{T}_{w}})\sqrt{\text{R}{{\text{a}}_{\ell x}}}}{x}{{{\theta }'}_{\ell }}(0)$ (8.382)

and the local Nusselt number is $N{{u}_{x}}=\frac{{{{{q}''}}_{w}}x}{{{k}_{m\ell }}({{T}_{sat}}-{{T}_{w}})}=\frac{Ra_{\ell x}^{1/2}}{\sqrt{\pi }\text{erf(}{{\eta }_{\delta }}/2)}$ (8.383)

where ηδ is function of Jakob number, $\text{J}{{\text{a}}_{\ell }}$, as indicated by eq. (8.381). Cheng (1981) recommended that eq. (8.383) can be approximated using $N{{u}_{x}}={{\left( \frac{1}{2J{{a}_{\ell }}}+\frac{1}{\pi } \right)}^{1/2}}Ra_{\ell x}^{1/2}$ (8.384)

In practical application, the average Nusselt number is often of the interest. It can be obtained by integrating eq. (8.384): $\overline{Nu}=\frac{\bar{h}L}{{{k}_{m\ell }}}={{\left( \frac{1}{J{{a}_{\ell }}}+\frac{2}{\pi } \right)}^{1/2}}Ra_{\ell L}^{1/2}$ (8.385)

## References

Cheng, P., 1981, “Film Condensation Along an Inclined Surface in a Porous Medium,” International Journal of Heat and Mass Transfer, Vol. 24, pp. 983-990.